14-07-2019, 08:20 AM
(This post was last modified: 14-07-2019, 09:15 AM by Colin Morgan.)
Hi Bob,
The skyward force needs to resist the weight. Because the coefficient of friction between the bike wheel and the wall is less than one, the downwards force needs to be higher than the weightforce of 1G. If the coefficient of friction is 0.7 - a reasonable figure between wood and hard rubber - then slip won't occur for a downforce of the weight divided by 0.7 - as you say, about 1.5G.
Yes, if the track were wet and slippery, then a significantly higher downforce would be needed - insufficient speed would mean instant disaster. This is yet another hazard from having a lion as a passenger - as if any more were needed? That picture is priceless.
Regards,
Colin
The skyward force needs to resist the weight. Because the coefficient of friction between the bike wheel and the wall is less than one, the downwards force needs to be higher than the weightforce of 1G. If the coefficient of friction is 0.7 - a reasonable figure between wood and hard rubber - then slip won't occur for a downforce of the weight divided by 0.7 - as you say, about 1.5G.
Yes, if the track were wet and slippery, then a significantly higher downforce would be needed - insufficient speed would mean instant disaster. This is yet another hazard from having a lion as a passenger - as if any more were needed? That picture is priceless.
Regards,
Colin